Java Example: Program

Showing posts with label Program. Show all posts

Monday, August 20, 2012

how to count selected Character from a sentence in java

Output:

C contents 3 times.

DuplicateCharacter.java

package com.swain.cell;

import java.util.HashMap;

public class DuplicateCharacter {

/**

* @param args

public static void main(String[] args) {

// TODO Auto-generated method stub

String str = "Character duplicate word example java";

char selectedchar='C';

char ch1[]=str.toUpperCase().toCharArray();

HashMap<Character,Integer> hm=new HashMap<Character,Integer>();

for(int i=0; i<ch1.length; i++)

{

char ch=ch1[i];

hm.put(ch,(hm.get(ch)==null?1:hm.get(ch)+1));

}

System.out.println(selectedchar+" contents " + hm.get(selectedchar)+ " times.");

}

// amazon ebay shopbob.com hotels.com canon newegg.com Google

how to count selected word in string using java

Output:

java contents 3 times.

package com.swain.cell;

import java.util.HashMap;

import java.util.StringTokenizer;

public class DuplicateString {

/**

* @param args

public static void main(String[] args) {

// TODO Auto-generated method stub

String str = "java java android android java example";

String selectedword="java";

StringTokenizer t = new StringTokenizer(str);

HashMap<String,Integer> hms=new HashMap<String,Integer>();

while(t.hasMoreTokens())

{

String word = t.nextToken();

hms.put(word,(hms.get(word)==null?1:hms.get(word)+1));

}

System.out.println(selectedword+" contents " + hms.get(selectedword)+ " times.");

}

}

Check here video.

How to count duplicate characters from a sentence in java

Output :

DuplicateCharacter.java

package com.swain.cell;

import java.util.HashMap;

public class DuplicateCharacter {

/**

* @param args

public static void main(String[] args) {

// TODO Auto-generated method stub

String str = "Character duplicate word example java";

char ch1[]=str.toCharArray();

HashMap<Character,Integer> hm=new HashMap<Character,Integer>();

for(int i=0; i<ch1.length; i++)

{

char ch=ch1[i];

hm.put(ch,(hm.get(ch)==null?1:hm.get(ch)+1));

}

System.out.println("No of Characters are : "+hm.toString());

}

How to count duplicate words from a sentence in java

Output :

no of word {android=2, java=3, example=1}

DuplicateString.java

package com.swain.cell;

import java.util.HashMap;

import java.util.StringTokenizer;

public class DuplicateString {

/**

* @param args

public static void main(String[] args) {

// TODO Auto-generated method stub

String str = "java java android android java example";

StringTokenizer t = new StringTokenizer(str);

HashMap<String,Integer> hms=new HashMap<String,Integer>();

while(t.hasMoreTokens())

{

String word = t.nextToken();

hms.put(word,(hms.get(word)==null?1:hms.get(word)+1));

}

System.out.println("no of words " + hms.toString());

}

How to count word in string using java

Output:

Number of words are: 6

CountWords.java

package com.swain.cell;

import java.util.StringTokenizer;

public class CountWords {

/**

* @param args

public static void main(String[] args) {

// TODO Auto-generated method stub

String st="how to count word in java?";

int count=0;

StringTokenizer stk=new StringTokenizer(st," ");

while(stk.hasMoreTokens()){

String token=stk.nextToken();

count++;

}

System.out.println("Number of words are: "+count);

}

Friday, August 10, 2012

Palindrome

Output

Number is palindrome!

Source code

Palindrome.java

package com.swain.cell;

public class Palindrome {

public static void main(String [] args){

try{

int num= 161;

int n = num;

int rev=0;

for (int i=0; i<=num; i++){

int r=num%10;

num=num/10;

rev=rev*10+r;

i=0;

}

if(n == rev){

System.out.print("Number is palindrome!");

}

else{

System.out.println("Number is not palindrome!");

}

catch(Exception e){

System.out.println("Error");

}

Linear Search

Output

Linear Search List

44 index position 7

Source code

package com.swain.cell;

public class LinearSearch {

public static void main(String[] args)

{

System.out.println("Linear Search List");

int[] arr = {0,2879, 15, 29, 78, 26, 24, 44, 167, 13,24,47};

int i;

int num = 44;

boolean flag=false;

for(i=0; i<arr.length; i++){

if(arr[i]==num){

flag=true;

break;

}

}//for

if(flag){

System.out.println(num + " index position "+i);

}

else{

System.out.println(num + " no not found");

}

Binary Search

Output

---------------------------------

ENTER THE NUMBER TO BE SEARCHED

ENTER 10 NUMBERS FOR THE ARRAY

CONTENTS OF ARRAY ARE

NUMBER TO BE SEARCHED IS 8

NUMBER DOES NOT EXIST IN THE ARRAY

Source code

package com.swain.cell;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

public class BinarySearch {

public static void main(String args[])throws IOException{

int i;

InputStreamReader x=new InputStreamReader(System.in);

BufferedReader y=new BufferedReader(x);

int a[]=new int[10];

System.out.println("ENTER THE NUMBER TO BE SEARCHED");

int n=Integer.parseInt(y.readLine());

System.out.println("ENTER 10 NUMBERS FOR THE ARRAY");

for(i=0;i<10;i++)

{

a[i]=Integer.parseInt(y.readLine());

}

System.out.println("CONTENTS OF ARRAY ARE");

for(i=0;i<10;i++)

{

System.out.println(a[i]);

}

System.out.println("NUMBER TO BE SEARCHED IS "+n);

int p=-1,mid,l=0,u=9;

while(l<=u)

{

mid=(l+u)/2;

if(a[mid]==n)

{

p=mid;

break;

}

else if(n> a[mid])

{

l=mid+1;

}

else if(n<a[mid])

{

u=mid-1;

}

if(p==-1)

{

System.out.println("NUMBER DOES NOT EXIST IN THE ARRAY");

}

else

{

System.out.println("NUMBER EXISTS AT THE INDEX "+p);

}

}

// amazon ebay shopbob.com hotels.com canon newegg.com